Chemistry Reacts with Hydroxide & Lewis Structures Exam Practice: Chemistry Answers 2021

Chemistry Reacts with Hydroxide & Lewis Structures Exam Practice: Chemistry Answers 2021

Question Title:

Chemistry Reacts with Hydroxide & Lewis Structures Exam Practice

Full Question:

Unformatted Attachment Preview

1. The initial rates were measured under a variety of conditions for the reaction where
(CH3)3CCHICH3 reacts with hydroxide. From those experiments, the rate law was
determined to be rate = k[(CH3)3CCHICH3][–OH].
a. (2 points) What information does the rate law provide about the mechanism of this
reaction?
b. (4 points) Using curved arrows, draw the mechanism for this reaction. Make sure to
include complete Lewis structures for any products that form.
c. (1 points) What would be different about your mechanism if the rate law had been
determined to be rate = k[(CH3)3CCHICH3]?
2. Consider the reaction where 3A ⇌ 2B. The reaction starts with 1.0 M A and no B. After 7
minutes, the concentration of A has decreased to 0.1 M.
a. (4 points) Complete an ICE table for this reaction.
(M)
3A
Initial:
1.0
Change:
Equilibrium:

2B
0
b. (2 points) On the graph below use a solid line (––––) to plot the [A] vs time for 10
minutes.
c. (2 points) On the same set of axes, use a dashed or dotted line ( – – – – ) to plot the [B] vs
time for 10 minutes.
d. (1 points) Write an expression for the equilibrium constant for this reaction in terms of
[A] and [B]. Do not include numbers or carry out a calculation here!
e. (2 points) Using your answer to part d, calculate the equilibrium constant for this
reaction. Include your work to earn full credit.
f. (1 points) Imagine that at 9 minutes, some of the product, B, was removed from the
reaction flask. What do you predict would happen to the [A]? Write “increase”,
“decrease”, or “stay the same”. Do not include an explanation here.
1
2
3
4
5
6
7
8
Practice Multiple Choice Questions
1. Which reaction do you think has a larger rate constant (faster rate) and why?
I. HCl + H2O → H3O+ + –Cl
II. CH3Br + –OH → CH3OH + Br–
A. I, because acid base reactions don’t have a high activation energy, since the H being transferred is
partially ionized.
B. I, because HCl is a gas, and therefore can react very quickly
C. II, because there is a C-Br bond breaking in the rate determining step
D. II, because hydroxide is a strong base
Explanation: The rate constant depends on the activation energy – which depends on bond breaking
steps. C explains why II would go slower. B and D are not answering the question.
2. At which time is this system at equilibrium? (Why is it at equilibrium at this time? How do you know?)
Answer: C
Explanation: At equilibrium, both the forward and reverse reactions occur at the same rate, so there is
no further change in concentration.
3. For the reaction A + B → C the rate equation is: rate = k[A]2[B]
If the concentration of A is doubled and the concentration of B is doubled, by what factor will the rate
increase?
A. 4
B. 2
C. 8
D. 16
4. A radioactive tracer Tc has rate constant for decay of 1.05 × 10–2 hr–1. What is the half-life for the
decay?
A.
B.
C.
D.
5
66 hours
66 days
0.693 hrs
0.480 hrs
What could affect both the rate of a reaction and the equilibrium constant?
I. change in temperature
II. change in concentrations of reactants
III. presence of a catalyst
1
A. I and III
B. I
C. I and II
D. all of them
Explain what effect each answer (I, II, and III) has on the rate and equilibrium constant.
I. Increasing T will increase the rate (more energetic collisions) and change the value of K.
II. Will only increase the rate (it will change the position of equilibrium – but NOT the value of K)
III. Increases rate – but does not change the value of K. A catalyst provides an alternate path.
6. What is the age of bottled wine that has a tritium (H-3) content that is 60% of the tritium in freshly
bottled wine. Tritium as a half-life of 12.3 years and decays by beta decay (a first-order reaction.
A.
B.
C.
D.
E.
7.
0.029 yr
7.4 yr
9.1 yr
16 yr
35 yr
Which of the labels on this diagram indicates the transition state for the forward rate-determining step?
Answer: B
Explanation: B is the transition state for the forward rate-determining step. The energy change between
A and B is much greater than between C and D. C is the intermediate. D is the transition state for the
second step.
8.
What is the equilibrium constant expression for the following equilibrium?
3Fe(s) + 4H2O(g)  Fe3O4(s) + 4H2(g)
A.
K = [H2]4
B.
K = [H2]
[H2O]
C.
K = [H2]4
[H2O]4
D.
K = [Fe2O3][H2]4
[Fe]3[H2O]4
2
9.
This system shows a reaction A + B  AB at
equilibrium, which other system is at equilibrium?
Answer: D
Explanation: You can calculate the K from the initial system K = [AB]/([A][B]) = (3)/(3)(3) = 3/9 =
1/3. None of the other systems have this ratio of products and reactants.
Questions 10-12 are about the same acid:
10. If the pH of a 0.15 M acid is 3.6, what is the Ka?
A.
B.
C.
D.
1.2 × 10-3
2.5 × 10-4
4.2 × 10-7
1.0 × 10-10
11. What is the % ionization of this acid?
A.
B.
C.
D.
0.80%
0.17%
99.9%
1.07%
12. Which of these diagrams represents a concentrated solution of this acid?
Answer: D
3
13. For a system at equilibrium
A.
B.
C.
D.
ΔG = 0
ΔG° = 0
Both ΔG and ΔG° = 0
None are true
14. Consider the reaction A + B  2C. The equilibrium constant is 1.0. If a 1 L solution containing 10 mol
A, 2 mol B and 10 mol C is allowed to react, what will be the concentration of A when equilibrium is
reached?
A.
B.
C.
D.
> 10 M
>Approximate cost: $8 per page.
>Choose your own tutor.
>Get free revision, plagiarism reports, and a list of sources.
>Release the money only after delivery[/vc_message]

How it Works

hw

Why you should post this Chemistry question now.

Flawless Deliveries
Our tutors deliver fault free assignments after careful and detailed research. All instructions are followed to the letter.

100% Originality Guarantee
Every task delivered to students on our platform has 100% originality guarantee. Find plagiarism, get 100% money back.

Timely Deliveries
When you post a question here, we assure on-time delivery, or 100% money back. You cannot miss deadlines with us.

24/7 Customer Support
Our support agents are always online, ready to help you when using our platform. It only gets better.

Student-Friendly Prices
Getting quality help should not break your pocket. Find instant quality help for whatever budget you have.

Free Revisions
You can request your tutor for as many revisions as needed to ensure you are 100% satisfied with our services.

100% Privacy
Every action you take on our platform is anonymous. Once you receive your help, it is almost as if you weren?t here.

100% Refunds
If a tutor breaks any of our guarantees, you get 100% money back to ask questions in the future. No questions.

Here are other questions on different subjects that our tutors have handled with excellent results.

The first ones are FIN 240 WNC Contracts and Torts Seller Had Made False Statements Project and MNSU Physics Force Vector in A Liquid Container Lab Report which required in-depth research and computations. The third and fourth ones are Chemistry Reacts with Hydroxide & Lewis Structures Exam Practice and UCSD How to Fix School Segregation in The US Paper, which called for experts to help with online quizzes. All these were answered for students who were looking for study assistants for homework help 2021

Reviews from Students; Verified by Trustalyze

Studyhelp247 Exceeded my expectations.

Rated 5 out of 5
3 years ago

I believe in studyhelp247 now. Here, I found the best tutor to assist me with a complex math task. It was seamless using the site.

Avatar for SdfDsf
SdfDsf

Response from Studyhelp247

Thank you for using our platform to find academic help. We are happy that you found what you were looking for.

By far, the best source of affordable custom writing solutions.

Rated 5 out of 5
3 years ago

I came to studyhelp247 after seeing an ad and they have been great. It is quite affordable owing to the fact that there are no service fee charges.

Avatar for Student01
Student01

Response from Studyhelp247

Thank you for the great review. We are committed to providing the best platform to foster student excellennce. 🙂

Very responsive support

Rated 5 out of 5
3 years ago

I have enjoyed using studyhelp247. The support was very responsive and I received quality work

Avatar for Alsalem
Alsalem

Response from Studyhelp247

Thank you.
Our support agents are always available to assist you with any issue.

Great work done for me by Anastacia.

Rated 5 out of 5
3 years ago

Thank you for the great work that you delivered. I will be back for more. 🙂

Avatar for Elsie
Elsie

Response from Studyhelp247

Thank you for using our site.