This question was previously asked in

NIMCET 2018 Official Paper

Option 2 : 16, 8

NIMCET 2020 Official Paper

1469

120 Questions
480 Marks
120 Mins

The correct answer **16, 8.**

__Key Points__

- (235)R1 = (565)10 = (1065)R2 …….(1)
- (235) R1 = 2R1^2 + 3R1 + 5 = 565 …………(2)
- By solving quadratic equation (2) we get..
- R1= 16 & -17.5
- Since radix cannot be negative so ignore 17.5
- Hence R1=16
- Putting value of R1 in (1) we get -:
- (235)16 =(1065)R2
- 2*16^2+3*16^1+5*16^0=1* R2^3 + 0* R2^2 + 6* R2^1 + 5* R2^0
- 512+48+5= R2^3+6R2+ 5
- 560= R2^3+6R2
- R2^3+6R2-560=0
- By solving above cubic equation we get-:
- R2 = 8
- R2 = -4 + i * 7.34847
- R2 = -4 - i * 7.34847
- Radix cannot be imaginary number so ignoring imaginary numbers
- We get R2 = 8
- From options we can see option B) is correct answer. Where R1 =16 and R2 =8.